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Question

An electric dipole moment P=(2.0^i+3.0^j)μ is placed in a uniform electric field E=(3.0^i+2.0^k)×105NC1 .

A
The torque that E exerts on P is (0.6^i0.4^j0.9^k) Nm
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B
The potential energy of the dipole is 0.9 J
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C
The potential energy of the dipole is 0.6 J
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D
If the dipole is rotated in the electric field, the maximum potential energy of the dipole is 1.3 J
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Solution

The correct options are
A The torque that E exerts on P is (0.6^i0.4^j0.9^k) Nm
B If the dipole is rotated in the electric field, the maximum potential energy of the dipole is 1.3 J
C The potential energy of the dipole is 0.6 J
Torque τ=P×E=(2.0^i+3.0^j)106×(3^i+2^k)105=0.9^k0.4^j+0.6^i
Potential energy |U|=|P.E|=0.6J
If the dipole is rotated in field direction so for maximum potential
Umax=|P||E|cos0=22+32×106×32+22×105=1.3J

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