Question

An electric dipole of dipole moment $20\times {10}^{-6}C$ is enclosed by closed surface. What is the net electric flux coming out of this surface?

Answer 1

$\text{Step 1: Applying Gauss Law}$

Consider the closed surface enclosing the dipole as Gaussian Surface

Dipole is made of two equal and opposite point charge.

So, $q_{\text{inside}}=-q+q=0$

So, By Gauss Law:

Flux $=\frac{q_{\text{inside}}}{{ϵ}_0}=\frac{0}{{ϵ}_0}=0$
$\therefore$ There will be no flux through the surface.