An electric heater draws a current of 3.4A from the 220V supply line. What current will it draw when connected to 110 V supply line?

6.8 A

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1.7 A

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13.6 A

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27.2 A

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Solution

The correct option is A 1.7 A
Ohm's Law, $V = I R$
Therefore, $R = \frac{I}{V}$
So, $R = \frac{220}{3.4} = 64.7 Ω$
Now,
$V = 110 v o l t$ and $R = 64.7 Ω$
Hence, $I = \frac{V}{R} = \frac{110}{64.7} = 1.69 A$

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