An electric kettle is marked with $500 W; 250 V .$ What is the resistance of its heating filament?

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Solution

Step 1: Given
$P o w e r = 500 W V o l t a g e = 250 V$
Step 2: Find resistance
The formula of power is
$P = \frac{V^{2}}{R} [w h e r e P = p o w e r, V = p o t e n t i a l, R = r e s i s \tan c e] N o w, R = \frac{V^{2}}{P}$
Putting the given value in the formula
$R = \frac{250 \times 250}{500} = 125 o h m s$
Hence, the resistance of the filament is $125 o h m s$ .

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An electric kettle is marked with 500W;250V. What is the resistance of its heating filament?

Step 1: GivenPower=500WVoltage=250VStep 2: Find resistance The formula of power isP=V2R[whereP=power,V=potential,R=resistance]Now,R=V2PPutting the given value in the formula R=250×250500=125ohmsHence, the resistance of the filament is 125ohms.

An electric kettle is marked with $500 W; 250 V .$ What is the resistance of its heating filament?