Question

An electric kettle rated as $1200W$ at $220V$ and a toaster rated at $1000W$ at $220V$ are both connected in parallel to a source of $220V$. If the fuse connected to the source blows when the current exceeds $9.0A$, can both appliances be used at the same time? Illustrate your answer with calculations.

Answer 1

Given,

$P_1=1200W,P_2=1000W$
$V=220V$

Fuse rating $9A$, it means if the current exceeds from $9A$ then fuse wire will break, and current for appliances will be zero.

We know,

$P=VI$
Total current required,
$I=\frac{P}{V}$

In parallel combination total power -

$P=P_1+P_2$

$\Rightarrow I=\frac{P_1+P_2}{V}$

$\Rightarrow I=\frac{1200+1000}{220}$

$\Rightarrow I=10A$

If both the appliances are switched on together, the fuse will get burnt. So, both the appliance cannot be used at the same time.