An electric motor of power $100 W$ is used to drive the stirrer in a water bath. If $50$ % of the energy supplied to the motor is spent in stirring the water, find the work done on water in one minute.

6000 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

50 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3000 J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

100 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $3000 J$
Power supplied $= 100 W$ , time $t = 60 s$
So, power used in stirring water = $50$ % of the power supplied $= \frac{50}{100} \times 100 W = 50 W$
Work done on water = power used $\times$ time $= 50 W \times 60 s = 3000 J$

Suggest Corrections

Similar questions

Q. AN electric motor of power

100 W

is used to drive the stirrer in a water bath . If

50 %

of the energy supplied to the motor is spent in stirrering the water , work done on the water in

1 m i n

Q. An electric motor of power 300 W is used to drive the stirrer in a water bath. The work done in one minute, if 60 % of the energy of the motor is utilized to drive the stirrer will be

Q. An installation consisting of an electric motor driving a water pump left

75 L

of water per second to a height of

4.7 m

. If the motor consumes a power of

5 k W

, then the efficiency of the installation is

In a hydroelectric power plant, moving water is used for driving the wheels of a turbine to generate electricity. If the change in kinetic energy of turbine is 1200 J in 2 minutes then the power generated is

Q. A motor can pump up water to fill a tank of volume

50 m^{3}

25

minutes which is placed at of

20 m

. If efficiency of the motor is

40 %

calculate the power of the motor.

Join BYJU'S Learning Program

An electric motor of power 100W is used to drive the stirrer in a water bath. If 50% of the energy supplied to the motor is spent in stirring the water, find the work done on water in one minute.

The correct option is B 3000JPower supplied=100W, time t=60sSo, power used in stirring water = 50% of the power supplied=50100×100W=50WWork done on water = power used × time =50W×60s=3000J

An electric motor of power $100 W$ is used to drive the stirrer in a water bath. If $50$ % of the energy supplied to the motor is spent in stirring the water, find the work done on water in one minute.

The correct option is B $3000 J$
Power supplied $= 100 W$ , time $t = 60 s$
So, power used in stirring water = $50$ % of the power supplied $= \frac{50}{100} \times 100 W = 50 W$
Work done on water = power used $\times$ time $= 50 W \times 60 s = 3000 J$