An electric pole, 15 metres high, casts a shadow of 10 metres. The height of a tower that casts a shadow of 300 metres under similar conditions is _____ m.

140

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480

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450

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280

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Solution

The correct option is C 450
Let us assume height of the tower that casts a shadow of 300 m is x m.

Height of pole (H) and its shadow (S) are directly proportional to each other. So,

$\frac{H}{S} = c o n s t a n t$
$\frac{H_{1}}{S_{1}} = \frac{H_{2}}{S_{2}}$
$\frac{15}{10} = \frac{x}{300}$
$x = 450 m$

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An electric pole, 15 metres high, casts a shadow of 10 metres. The height of a tower that casts a shadow of 300 metres under similar conditions is _____ m.

The correct option is C 450Let us assume height of the tower that casts a shadow of 300 m is x m. Height of pole (H) and its shadow (S) are directly proportional to each other. So, HS=constant H1S1=H2S2 1510=x300 x=450 m