An electric refrigerator rated $1$ kW operates $5$ hours /day.The cost of energy to operated it for $30$ days at $R s .3 .00$ per unit is

R s .500

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R s .300

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R s .450

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R s .400

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Solution

The correct option is C $R s .450$
Given,
$T i m e = t = 5 h r s$
$Energy = P\times t =1\times5 = 8
KWh$
Energy consumption in one day $= 5 K W h$
Energy consumption in the month of June $= 5 \times 30 = 150 K W h$
Total cost $= m o n t h l y c o n s u m p t i o n \times r a t e$ $= R s 150 \times 3 = R s 450$

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