An electric refrigerator rated $600 W$ operates $8 h o u r s / d a y$ . What is the cost of the energy to operate it for $30$ days at $R s . 4.00 p e r k W h$ ?

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Solution

Power of refrigerator $= 600 W = 0.6 k W$
Total operation hours $8 \times 30$ $= 240 h$
Work done or total electrical energy $(W) =$ $0.6 \times 240$ $= 144 k W h$
Total cost of energy to operate $= R s .$ $(144 \times 4.00)$ $= R s . 576$

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