An electric room heater has a resistance of 20 - and operates at 220 V for 5 minutes- Calculate the heat energy dissipated by it in kilojoules-

The correct option is D 726 J R = 20 #160; Ω, #160; V = 220 #160; V, #160; t = 5 × 60 = 300 #160; s Energy dissipated = V^2× tR ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Units and Dimensions

An electric r...

Question

An electric room heater has a resistance of $20 Ω$ and operates at $220 V$ for 5 minutes. Calculate the heat energy dissipated by it in kilojoules.

66 k J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1320 k J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

161 k J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

726 J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $726 J$
$R = 20 Ω, V = 220 V, t = 5 \times 60 = 300 s$
Energy dissipated $= \frac{V^{2} \times t}{R}$
$= \frac{{(220)}^{2} \times 300}{20} = 726, 000 k J = 726 J$

Suggest Corrections

Similar questions

Q. An electric heater draws a current of

10 A

and its element has a resistance

20 Ω

. If the heater is switched on for 6 minutes, calculate energy released in kilojoules.

Q. An electric immersion heater with a resistance of 40 ohms is connected to a 240 V power supply. Calculate the current flowing through the heater and the amount of heat energy produced by the heater in 30 minutes.

An electric heater uses 600 kJ of electrical energy in 5 minutes. Calculate its power rating.

An electric heater of resistance 8 ohm draws 15C of charge per second suppose it happens for a period of 2 hours, calculate the heat energy derived by the heater.

An electrical appliance having a resistance of $200 Ω$ is operated at 200 V. Calculate the energy consumed by the appliance in 5 minutes (i) in joule, (ii) in kWh.

Join BYJU'S Learning Program

An electric room heater has a resistance of 20Ω and operates at 220V for 5 minutes. Calculate the heat energy dissipated by it in kilojoules.

The correct option is D 726JR=20Ω,V=220V,t=5×60=300sEnergy dissipated =V2×tR =(220)2×30020=726,000kJ=726J

An electric room heater has a resistance of $20 Ω$ and operates at $220 V$ for 5 minutes. Calculate the heat energy dissipated by it in kilojoules.

The correct option is D $726 J$
$R = 20 Ω, V = 220 V, t = 5 \times 60 = 300 s$
Energy dissipated $= \frac{V^{2} \times t}{R}$
$= \frac{{(220)}^{2} \times 300}{20} = 726, 000 k J = 726 J$