An electrical appliance is rated at 1000 KVA, 220V. If the appliance is operated for 2 hours, calculate the energy consumed by the appliance in:
(i) kWh.
(ii) joule.

Open in App

Solution

(i) Let Energy consumed $= P o w e r \times T i m e$
$= 1000 \times 2 = 2000 k W h$
(ii) $1 k W h = 3.6 \times 10^{6} J$
$∵$ Energy consumed $= 2000 \times 3.6 \times 10^{6} J$
$= 7.2 \times 10^{9} J$ .

Suggest Corrections

Similar questions

An electrical appliance having a resistance of $200 Ω$ is operated at 200 V. Calculate the energy consumed by the appliance in 5 minutes (i) in joule, (ii) in kWh.

Q. An electrical appliance is rated 1500 W, 250 V. This appliance is connected to 250 V mains.
Calculate :
(i) The current drawn
(ii) The electrical energy consumed in 60 hours
(iii) The cost of electrical energy consumed at Rs. 2.50/kWh.

An electrical appliance is rated 1500 W, 250 V. This appliance is connected to 250 V mains. The electrical energy consumed in 60 hours is:

Q. An electrical appliance having a resistance of

200 Ω

is operated at

200 V

. What is the energy consumed by the appliance in 5 minutes in joules ?

Q. An electrical appliance having a resistance of

200 Ω

is operated at

200 V

. What is the energy consumed in kWh ?

Join BYJU'S Learning Program

An electrical appliance is rated at 1000 KVA, 220V. If the appliance is operated for 2 hours, calculate the energy consumed by the appliance in: (i) kWh.(ii) joule.

(i) Let Energy consumed =Power×Time=1000×2=2000kWh(ii) 1kWh=3.6×106J∵ Energy consumed =2000×3.6×106J=7.2×109J.

An electrical appliance is rated at 1000 KVA, 220V. If the appliance is operated for 2 hours, calculate the energy consumed by the appliance in:
(i) kWh.
(ii) joule.

(i) Let Energy consumed $= P o w e r \times T i m e$
$= 1000 \times 2 = 2000 k W h$
(ii) $1 k W h = 3.6 \times 10^{6} J$
$∵$ Energy consumed $= 2000 \times 3.6 \times 10^{6} J$
$= 7.2 \times 10^{9} J$ .