Question

An electrical appliance is rated at $1000KVA,220V.$ If the appliance is operated for $2$ hours, calculate the energy consumed by the appliance in:
$Joule$

Answer 1

Step 1 Given data:
$$\begin{gathered} P=1000kVA=1000kW \\ t=2h \\ V=220V \end{gathered}$$

Step 2 Formula used:
Energy consumed in $kWh$ is
$E=P\times t$
Where, $E$ is the Energy consumed, $P$ is the Power, $t$ is the time.

Step 3 Calculating the energy consumed by the appliance in $Joule$:
Energy consumed in $kWh$ is given by $E=P\times t$
$E=1000\times 2=2000kWh.$
We know that,
$1kWh=3.6\times {10}^{6}J$
Now, energy consumed in $J$ is $2000\times 3.6\times {10}^{6}J$
$E=7.2\times {10}^{9}J$
Therefore, the energy consumed by the appliance in $J$ is $7.2\times {10}^{9}J$.