An electrochemical cell is set up as
$P t, H_{2} (1 a t m) | H C l (0.1 M) | | {C H}_{3} C O O H (0.1 M) | H_{2} (1 a t m), P t$
The emf of the cell is not zero because:

the two acids are different

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the molarities are same

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it is a concentration cell

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the

p H

values are different for the two acid

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Solution

The correct option is
A
the two acids are different

$P t, H_{2} (1 a t m) | H C l (0.1 M) | {C H}_{3} C O O H (0.1 M) | H_{2} (1 a t m) |$
$\to$ $H C l$ is a strong acid and acetic acid is a weak acid.
$\to$ Therefore $H C l$ dissociates completely where as acetic acid is a weak acid it does not dissociate completely.
The emf of a cell depends on the concentrations of ion and on gas pressures.
$\to$ Hence concentration is different, pH will be different
$∴ E_{c e l l} \neq 0$

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