An electromagnetic wave going through vacuum is described by E - Eo sinkx-t- B - Bo sinkx-t- Which of the following equation is true

E_0/B_0=C. also k=2π/λ and w=2π v These relation gives E_0K=B_0w ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Wave Equation of EM Waves

An electromag...

Question

An electromagnetic wave going through vacuum is described by E = $E_{o} s i n (k x - ω t); B = B_{o} s i n (k x - ω t);$ . Which of the following equation is true

$E_{o} k = B_{o} ω$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$E_{o} ω = B_{o} k$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$E_{o} B_{o} = ω k$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
$E_{o} k = B_{o} ω$

$\frac{E_{0}}{B_{0}} = C .$ also $k = \frac{2 π}{λ}$ and $w = 2 π v$

These relation gives $E_{0} K = B_{0} w$

Suggest Corrections

Similar questions

An electromagnetic wave going through vacuum is described by E = $E_{o} s i n (k x - ω t); B = B_{o} s i n (k x - ω t);$ . Which of the following equation is true

Q. Electric field and magnetic field of an electromagnetic wave propagating through a medium is given by,

E = E_{\circ} sin (k x - ω t)

and

B = B_{\circ} sin (k x - ω t)

respectively, then -

Q. An electromagnetic wave passing through vacuum is described by the equations.

E = E_{0} sin (k x - ω t)

and

B = B_{0} sin (k x - ω t)

. Then.

Q. An electromagnetic wave, going through vacuum is described by

E = E_{0} sin (k x - ω t)

. Which of the following is independent of wavelength?

Q. An electromagnetic wave going through vacuum is described by
E = E₀ sin (kx − ωt); B = B₀ sin (kx − ωt).
Then,
(a) E₀ k = B₀ ω
(b) E₀ B₀ = ωk
(c) E₀ ω = B₀ k
(d) None of these

Join BYJU'S Learning Program

An electromagnetic wave going through vacuum is described by E = Eo sin(kx−ωt); B =Bo sin(kx−ωt);. Which of the following equation is true

The correct option is A Eok=Boω E0B0=C. also k=2πλ and w=2π v These relation gives E0K=B0w

An electromagnetic wave going through vacuum is described by E = $E_{o} s i n (k x - ω t); B = B_{o} s i n (k x - ω t);$ . Which of the following equation is true

The correct option is A
$E_{o} k = B_{o} ω$

$\frac{E_{0}}{B_{0}} = C .$ also $k = \frac{2 π}{λ}$ and $w = 2 π v$

These relation gives $E_{0} K = B_{0} w$