An electromagnetic wave of frequency v=3.0MHz passes from vacuum into a dielectric medium with permittivity ϵ=4.0. Then
A
wavelength is halved and frequency remains unchanged.
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B
wavelength is doubled and frequency becomes half.
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C
wavelength is doubled and frequency remains unchanged.
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D
wavelength and frequency both remain unchanged.
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Solution
The correct option is A wavelength is halved and frequency remains unchanged. Frequency remains constant during refraction. vmed=1√μ0ϵ0×4=c2 λmedλair=vmedvair=c2c=12 ∴ wavelength is halved and frequency remains unchanged.