An electron beam accelerated from rest through a potential difference of 5000 V in a vacuum is allowed to impinge on a surface normally. The incident current is 50 μA and if the electrons come to rest on striking the surface, the force on it is
A
1.1924×10−8N
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B
2.1×10−8N
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C
1.6×10−8N
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D
1.6×10−6N
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Solution
The correct option is A1.1924×10−8N Total current is A=50×10−6A
Charge of a electron e=1.6×10−19C
Total number of electron per second n=Ae=3.125×1014
Total energy KE=eV=1.6×10−19×5000=8×10−16J
Force on wall will be equal to change in momentum of n electron in one second
Let P = momentum and m be the mass of electron
So KE=P22m
So P2=2m×KE
P=3.8×10−23
Total force is F=nP=3.125×1014×3.8×10−23=1.19×10−8N