An electron beam accelerated from rest through a potential difference of 5000V in vacuum is allowed to impinge on a surface normally. The incident current is 50μA and if the electron comes to rest on striking the surface, the force on it is
A
1.1924×10−8N
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B
2.1×10−8N
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C
1.6×10−8N
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D
1.6×10−6N
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Solution
The correct option is A1.1924×10−8N Energy =12mv2=5000eV =5000×1.6×10−19J mv2=√2×5000×(1.6×10−19)m =4×10−8√m Number of electrons striking per second is n=qe=Ite=50×10−6×11.6×10−19 ⇒n=31.25×1013 Force = Change of momentum per second =n(mv)=31.25×1013×4×10−8√m =125×105√9.1×10−31=1.1924×10−8N