Question

An electron has an orbital angular momentum equal to$\sqrt{6}\frac{h}{2\pi }$. How many z-components of this are possible?

• A. One
• B. Three
• C. Four
• D. Five

Answer 1

Answer: (D)

Five

As, orbital angular momentum is $\sqrt{l(l+1)}\frac{h}{2\pi }$ and given orbital angular momentum is $\sqrt{6}\frac{h}{2\pi }$ so $l=2$ and for $l=2$, z components are five.