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Question

An electron having mass (9.1 x 1031 kg) and charge (1.6 x 1019C) moves in a circular path of radius 0.5 m with a velocity 106 m/s in a magnetic fied. Strength of magnetic filed is

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Solution

Given : q=1.6×1019 C m=9.1×1027 kg v=106 m/s r=0.5 m
Radius of circular path r=mvqB
Or 0.5=9.1×1031×1061.6×1019×B
B=11.375×106 T=11.375 μT

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