Question

An electron in the hydrogen atom is excited from the first orbit to the fifth orbit. Find the change in energy of the electron in eV.

• A. $+(13.6\times 24)/25$
• B. $-(13.6\times 4)/5$
• C. $-(0.529\times 4)/5$
• D. $-(13.6\times 4)/9$

Answer 1

Answer: (A)

$+(13.6\times 24)/25$

For hydrogen atom , $Z=1$ and $\Delta E=-13.6[\frac{1}{n_2^2}-\frac{1}{n_1^2}]$
$n_1=1$ & $n_2=5$
$\Delta E=-13.6[\frac{1}{5^2}-\frac{1}{1^2}]$
$\Delta E=-13.6[\frac{1}{25}-1]$
$\Delta E$ = $\frac{13.6\times 24}{25}$eV