Question

An electron is moving in a circular path of radius $5.1\times {10}^{-11}$ m at a frequency of $6.8\times {10}^{15}$ revolutions/sec. The equivalent current is approximately equal to _______.

• A. $5.1\times {10}^{-3}A$
• B. $6.8\times {10}^{-3}A$
• C. $1.1\times {10}^{-3}A$
• D. $2.2\times {10}^{-3}A$

Answer 1

The correct option is C $1.1\times {10}^{-3}A$

Given:
Frequency, $v=6.8\times {10}^{15}rev/s$,
Time, $T=\frac{1}{frequency}=\frac{1}{6.8\times {10}^{15}}s$
Current is given by:
$i=\frac{Q}{T}=1.6\times {10}^{-19}\times 6.8\times {10}^{15}$
$=1.1\times {10}^{-3}A$.