An electron mass - 9-10-31kg- charge -1-6-10-19 C whose kinetic energy is 7-2-10-20 J is moving in a circular orbit in a magnetic field of 9- 10-5 weber-m2- The radius of the orbit is

R=√(2mK)/qB=√(2× 9×10^ 31×7.2× 10^ 20)/1.6×10^ 19× 9×10^ 5=2.5 cm ...

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Circular Kinematics

An electron m...

Question

An electron (mass = $9 \times 10^{- 31} k g,$ charge $= 1.6 \times 10^{- 19}$ C ) whose kinetic energy is $7.2 \times 10^{- 20}$ J is moving in a circular orbit in a magnetic field of $9 \times 10^{- 5} w e b e r / m^{2}$ . The radius of the orbit is

1.25 cm

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2.5 cm

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12.5 cm

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25.0 cm

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Solution

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Similar questions

9 \times 10^{- 31} k g,

= 1.6 \times 10^{- 19}

7.2 \times 10^{- 20}

9 \times 10^{- 5} w e b e r / m^{2}

1.6 \times 10^{- 19}

9 \times 10^{- 31}

4 \times 10^{6}

2 \times 10^{- 1}

1.6 \times 10^{- 19} C

9 \times 10^{- 31} kg

4 \times 10^{6} {ms}^{- 1}

2 \times 10^{- 1} T .

7.2 \times 10^{- 18} J

9 \times 10^{- 5} W b / m^{2}

(m a s s = 9 \times 10^{- 31} k g, c h a r g e = 1.6 \times 10^{- 19} C)

10^{6}

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