An electron moving with a velocity of $5 \times 10^{4} m s^{- 1}$ enters into a uniform electric field and acquires a uniform acceleration of $10^{4} m s^{- 2}$ in the direction of its initial motion. Calculate the time(in s) in which the electron would acquire a velocity double of its initial velocity.

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Solution

The correct option is B 5
Initial velocity of the electron is $u = 5 \times 10^{4} m / s$
Acceleration of the electron is $a = 10^{4} m / s^{2}$

From first equation of motion,
$v = u + a t$
$2 u = u + a t$
$t = u / a = (5 \times 10^{4}) / (10^{4}) = 5 s$
(C) 5

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Q. Question 22(i)
An electron moving with a velocity of

5 \times 10^{4} m s^{- 1}

enters into a uniform electric field and acquires a uniform acceleration of

10^{4} m s^{- 2}

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(i) Calculate the time in which the electron would acquire a velocity double of its initial velocity.

Q. Question 22(i)
An electron moving with a velocity of

5 \times 10^{4} m s^{- 1}

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10^{4} m s^{- 2}

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(i) Calculate the time in which the electron would acquire a velocity double of its initial velocity.

An electron moving with a velocity of 5 × 104 m per second enters into a uniform electric feild and acquires a uniform acceleration of 104 m per second square in the direction of its initial motion

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Q. Question 22(ii)
An electron moving with a velocity of

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enters into a uniform electric field and acquires a uniform acceleration of

10^{4} m s^{- 2}

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(ii) How much distance the electron would cover in this time?

Q. Question 22(ii)
An electron moving with a velocity of

5 \times 10^{4} m s^{- 1}

enters into a uniform electric field and acquires a uniform acceleration of

10^{4} m s^{- 2}

n the direction of its initial motion.

(ii) How much distance the electron would cover in this time?

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An electron moving with a velocity of 5×104 ms−1 enters into a uniform electric field and acquires a uniform acceleration of 104 ms−2 in the direction of its initial motion. Calculate the time(in s) in which the electron would acquire a velocity double of its initial velocity.

The correct option is B 5Initial velocity of the electron is u =5×104 m/sAcceleration of the electron is a=104 m/s2From first equation of motion, v=u+at2u=u+att=u/a=(5×104)/(104)=5s(C) 5

The correct option is B 5
Initial velocity of the electron is $u = 5 \times 10^{4} m / s$
Acceleration of the electron is $a = 10^{4} m / s^{2}$

From first equation of motion,
$v = u + a t$
$2 u = u + a t$
$t = u / a = (5 \times 10^{4}) / (10^{4}) = 5 s$
(C) 5