CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

An electron moving with a velocity of 5 × 104 m per second enters into a uniform electric feild and acquires a uniform acceleration of 104 m per second square in the direction of its initial motion

Calculate the time in which the electron would acquire a velocity double of its initial velocity and distance covered

Open in App
Solution

Given data:Initial velocity of the electron is,
u = 5 × 10^4 m/s

Acceleration of the electron is,
a = 10^4 m/s2

(i)

Using, v = u + at

=> 2u = u + at. [since v is double of Initial velocity (u)]

=> t = u/a = (5 × 10^4)/( 10^4) = 5 s

(ii)

Distance travelled in this time is,

S = ut + ½ at2

=> S = (5 × 10^4) × 5 + ½ × 10^4 × 5^2

=> S = 3,75,000 m

flag
Suggest Corrections
thumbs-up
0
BNAT
mid-banner-image