wiz-icon
MyQuestionIcon
MyQuestionIcon
6
You visited us 6 times! Enjoying our articles? Unlock Full Access!
Question

An electron of energy 11.2 eV undergoes an inelastic collision with a hydrogen atom in its ground state. [Neglect recoiling of atom as mH>>me]. Then in this case

A
The outgoing electron has energy 11.2 eV
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
The entire energy is absorbed by the H atom and the electron stops
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
10.2 eV of the incident electron energy is absorbed by the H atom and the electron would come out with 1.0 eV energy
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of the above
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 10.2 eV of the incident electron energy is absorbed by the H atom and the electron would come out with 1.0 eV energy
Now, the collision between electron and H-atom is inelastic which means that the Kinetic Energy before and after collision is not same.
Since mH>>me thus the majority of energy of the electron will be absorbed by the H-atom and the electron will travel with remaining energy.
Thus, 10.2 eV of the incident electron energy is absorbed by the H-atom and the electron would come net with 1.0 eV(c) energy.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Bohr's Model of Atom
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon