An electron tube was sealed off during manufacture at a pressure of 1-2 - 10-7 mm of mercury at 27oC- Its volume is 100 cm3- The number of molecules that remain in the tube is

The correct option is C 3.86 × 10^11 P=nkT n= P kT = hdg kT Number of molecules in the electron tube is =n× V= hdgV kT ⟹ n= hdg kT ...

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Standard IX

Chemistry

Atoms

An electron t...

Question

An electron tube was sealed off during manufacture at a pressure of $1.2 \times 10^{- 7}$ mm of mercury at $27^{o} C$ . Its volume is $100 c m^{3}$ . The number of molecules that remain in the tube is

2 \times 10^{16}

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3 \times 10^{15}

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3.86 \times 10^{11}

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5 \times 10^{11}

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Solution

The correct option is C $3.86 \times 10^{11}$
$P = n k T n = \frac{P}{k T} = \frac{h d g}{k T}$
Number of molecules in the electron tube is $= n \times V = \frac{h d g V}{k T}$
$⟹ n = \frac{h d g}{k T} = \frac{1.2 \times 10^{- 10} \times 13600 \times 9.8 \times 100 \times 10^{- 6}}{1.38 \times 10^{- 23} \times 300} = 3.86 \times 10^{11}$

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An electron tube was sealed off during manufacture at a pressure of 1.2×10−7 mm of mercury at 27oC. Its volume is 100cm3. The number of molecules that remain in the tube is

The correct option is C 3.86×1011P=nkTn=PkT=hdgkTNumber of molecules in the electron tube is=n×V=hdgVkT⟹n=hdgkT=1.2×10−10×13600×9.8×100×10−61.38×10−23×300=3.86×1011

An electron tube was sealed off during manufacture at a pressure of $1.2 \times 10^{- 7}$ mm of mercury at $27^{o} C$ . Its volume is $100 c m^{3}$ . The number of molecules that remain in the tube is