An element (at. Wt. = 50) crystallises in FCC lattice, with a = 0.50 nm. What is the density of the unit cell if it contains 0.25% Schottky defects? (useNA=6×1023) (a = Edge length of the unit cell)
A
2.0g/cc
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2.66g/cc
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
3.06g/cc
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B2.66g/cc Schottky defect is known to bring about a reduction in density due to the decrease in effective number of atoms per unit cell. Hence, n = 4×(1−0.25100)=3.99 ρ=ZMVNA ρ=3.99×50(0.5×10−9)3×1000×6×1023 ⟹ρ=2660kg/m3=2.66g/cc