An element (atomic mass $= 100 g / m o l$ ) having bcc structure has unit cell edge $400 p m$ . Then, density of the element is:

10.376 g / c m^{3}

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5.188 g / c m^{3}

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7.289 g / c m^{3}

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2.144 g / c m^{3}

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Solution

The correct option is D $5.188 g / c m^{3}$
$ρ = \frac{Z \times M}{N_{A} \times a^{3}} = \frac{2 \times 100}{6.023 \times 10^{23} \times (400 \times 10^{- 10})^{3}}$

$= 5.188 g / c m^{3}$

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Similar questions

An element (atomic mass 100 g/mol) having bcc structure has a unit cell edge of 400 pm. Then the density of the element is

An element (atomic mass 100g/mol) havingbcc structure has unit cell edge 400pm. Then density of the element is

100 g / m o l e

B C C

400 p m

B C C_{Z} = 2

100 g / m o l

B C C

400 p m

B C C, Z = 2

b c c

65

420 p m

g m s / c m^{3}

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