An element crystallises in a structure having F-C-C unit cell of an edge 200 pm - 200 gm of it contains 24 - 1023 atoms- What is the density-A- 41-6 gm - cm 3B- 42-6 gm - cm 3C- 43-6 gm - cm 3D- 44-6 gm - cm 3

The correct option is A 41.6 gm/cm^3ρ=Z.M/a^3.N_0=4 × 50/(200 × 10^ 10)^3 × 6.022 × 10^23≅ 41.6gm/cm^3 [∴ Mass of 24 × 10^23 atoms = 200 g, Mass of 6 × ...

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Standard XII

Chemistry

Coordination Number

An element cr...

Question

An element crystallises in a structure having F.C.C unit cell of an edge 200 pm, 200 gm of it contains 24 $\times 10^{23}$ atoms. What is the density?

41.6 g m / c m^{3}

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42.6 g m / c m^{3}

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43.6 g m / c m^{3}

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44.6 g m / c m^{3}

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Solution

The correct option is A $41.6 g m / c m^{3}$
$ρ = \frac{Z . M}{a^{3} . N_{0}} = \frac{4 \times 50}{(200 \times 10^{- 10})^{3} \times 6.022 \times 10^{23}} ≅ 41.6 g m / c m^{3}$
[ $∴$ Mass of 24 $\times 10^{23}$ atoms = 200 g, Mass of 6 $\times 10^{23}$ atoms = 50 g]

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An element crystallises in a structure having F.C.C unit cell of an edge 200 pm, 200 gm of it contains 24 ×1023 atoms. What is the density?

The correct option is A 41.6 gm/cm3ρ=Z.Ma3.N0=4×50(200×10−10)3×6.022×1023≅41.6gm/cm3 [∴ Mass of 24 ×1023 atoms = 200 g, Mass of 6 ×1023 atoms = 50 g]

An element crystallises in a structure having F.C.C unit cell of an edge 200 pm, 200 gm of it contains 24 $\times 10^{23}$ atoms. What is the density?

The correct option is A $41.6 g m / c m^{3}$
$ρ = \frac{Z . M}{a^{3} . N_{0}} = \frac{4 \times 50}{(200 \times 10^{- 10})^{3} \times 6.022 \times 10^{23}} ≅ 41.6 g m / c m^{3}$
[ $∴$ Mass of 24 $\times 10^{23}$ atoms = 200 g, Mass of 6 $\times 10^{23}$ atoms = 50 g]