An element crystallizes in bcc as well as fcc having edges 300 and 400 pm respectively. The ratio of their densities would be

1.18

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2.28

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3.38

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4.48

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Solution

The correct option is A 1.18
$\frac{d_{b c c}}{d_{f c c}} = \frac{\frac{2 \times M \times 10^{30}}{(300)^{3} \times N_{A}}}{\frac{4 \times M \times 10^{30}}{(400)^{3} \times N_{A}}} = \frac{(4)^{3}}{(3)^{3} \times 2} = \frac{64}{27 \times 2} 1.185$

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An element crystallizes in bcc as well as fcc having edges 300 and 400 pm respectively. The ratio of their densities would be

The correct option is A 1.18dbccdfcc=2×M×1030(300)3×NA4×M×1030(400)3×NA=(4)3(3)3×2=6427×21.185

The correct option is A 1.18
$\frac{d_{b c c}}{d_{f c c}} = \frac{\frac{2 \times M \times 10^{30}}{(300)^{3} \times N_{A}}}{\frac{4 \times M \times 10^{30}}{(400)^{3} \times N_{A}}} = \frac{(4)^{3}}{(3)^{3} \times 2} = \frac{64}{27 \times 2} 1.185$