Question

An element having a atomic mass $60$ has face centered cubic unite cell. The edge length of the unite cell is $400$pm. Then find out the density of an element.

Answer 1

$d=\frac{Z\times Mw.}{N_a\times a^3}$

$d=\frac{4\times 60}{6\times {10}^{2}3\left[\right(400\times {10}^{-}12{)}^3}$

$d\approx .62\times {10}^7$