An element R belongs to IVA(14) group and 3rd period in the periodic table. Arrange the elements that are placed below 'R' in increasing order of atomic size.

G e > S n > P b

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A s > S b > B i

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G e < S n < P b

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A s < S b < B i

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Solution

The correct option is C $G e < S n < P b$
R element is Si. Elements below it are ge,Sn, Pb. On moving down the group, the atomic size increases. Thus correct order of size is $P b > S n > G e$

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