Which of the following option correctly represent the correct set of stability order for the given ions?
(I) $G a^{3 +} > I n^{3 +} > T l^{3 +}$
(II) $G a^{3 +} < I n^{3 +} < T l^{3 +}$
(III) $G e^{+ 4} > S n^{+ 4} > P b^{+ 4}$
(IV) $G e^{+ 2} < S n^{2 +} < P b^{2 +}$
(V) $A s^{3 +} < S b^{3 +} < B i^{3 +}$

II, III, IV, V

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I, II, III, IV

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II, IV, V

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I, III, IV, V

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Solution

The correct option is D I, III, IV, V
On moving down the group, stability of higher oxidation state decreases due to inert pair effect.

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Similar questions

Stability of ions of $G e, S n, a n d P b$ will be in the order:

[1] P b^{2 +} > P b^{4}, S n^{2 +} > S n^{4 +}

[2] P b^{2 +} < P b^{4}, S n^{2 +} < S n^{4 +}

[3] P b^{2 +} > P b^{4}, S n^{2 +} < S n^{4 +}

[4] P b^{2 +} < P b^{4}, S n^{2 +} > S n^{4 +}

[5] S n^{2 +} < P b^{2 +}, S n^{4 +} > P b^{4 +}

[6] S n^{2 +} < P b^{2 +}, S n^{4 +} < P b^{4 +}

{S n}^{2 +} + {2 H g}^{2 +} ⟶ {H g}_{2}^{2 +} + {S n}^{4 +}

{G e}^{2 +} + {P b}^{4 +} ⟶ {p b}^{2 +} + {G e}^{4 +}

{T 1}^{+} + {G a}^{3 +} ⟶ {G a}^{+} + {T 1}^{3 +}

A^{o}

A s^{3 +}, S b^{3 +}

B i^{3 +}

S n^{2 +}, H g_{2}^{2 +}, P b^{2 +}, Z n^{2 +}, C u^{2 +}, C r^{3 +}, A s^{3 +}, M g^{2 +}, S b^{3 +}

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