An element with atomic mass z has two isotopes having atomic masses (z-1) and (z+2). Find out the percentage abundance of heavier isotope.
z=x(z+2)+(1−x)(z−1)
z=xz+2x+z−xz−1+x
0=3x−1⟹x=1/3
Therefore, the abundance of the heavier isotope is 33.3%