An element X has IP=1681 kJ/mole and EA=−333 kJ/mole then its electronegativity is:
A
(1681+333)/544
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B
(1681−333)/544
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C
(1681+(−333))/2
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D
208√1681+333544
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Solution
The correct option is C(1681+(−333))/2 Robert S. Mulliken proposed that the arithmetic mean of the first ionization energy (Ei) and the electron affinity (Eea) should be a measure of the tendency of an atom to attract electrons. As this definition is not dependent on an arbitrary relative scale, it has also been termed absolute electronegativity, with the units of kilojoules per mole or electron volts.