Question

An element $X$ having equivalent mass $E$ forms a general oxide $X_m{O}_n$, its atomic mass should be:

• A. $\frac{2\times E\times n}{m}$
• B. $2\times m\times E\times n$
• C. $\frac{E}{n}$
• D. $\frac{M\times E}{2\times n}$

Answer 1

The correct option is A $\frac{2\times E\times n}{m}$

Let atomic mass of metal $X$ is ${}^{\prime }{a}^{\prime }.$

Mass of metal $=a\times m$

Mass of oxygen $=16\times n$

Equivalent mass of element $=\frac{massofelement}{massofoxygen}\times 8$

$\begin{array}{c}E=\frac{am}{16n}\times 8\\ E=\frac{am}{2n}\\ \Rightarrow a=\frac{2En}{m}\end{array}$.

$\therefore$ Option $A$ is correct.