An elevator descends into a mine shaft at the rate of $6 m / m i n$ . If the descend stars from $10 m$ above the ground level, how long will it take to reach the shaft $350 m$ below the ground level?

Open in App

Solution

Rate of elevator $= 6 m / m i n$
and it was started $10 m$ above the ground level
Depth below ground level $= 350 m$
Total depth $= 350 + 10 = 360$
Time taken $= \frac{360}{6}$ minutes $= 60$ minutes $= 1$ hour

Suggest Corrections

Similar questions

An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach − 350 m.

An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach −350m? [4 MARKS]

An elevator descends into a mine shaft at the rate of 6 m/min. If the descend starts from 10 m above the ground level, how long it will take to reach the shaft 350 m below the ground level?

An elevator descends into a mine shaft at the of 6 Min/m . If the descent starts from 10m above the ground level, how long will it take to reach- 350m

Q. An elevator descends into a mine shaft at the rate of

15

m/min. If the descend starts from

10

m above the ground level, how long will it take to reach

- 140

Join BYJU'S Learning Program

An elevator descends into a mine shaft at the rate of 6 m/min. If the descend stars from 10 m above the ground level, how long will it take to reach the shaft 350 m below the ground level?

Rate of elevator =6 m/minand it was started 10 m above the ground level Depth below ground level =350 mTotal depth =350+10=360Time taken =3606 minutes =60 minutes =1 hour

An elevator descends into a mine shaft at the rate of $6 m / m i n$ . If the descend stars from $10 m$ above the ground level, how long will it take to reach the shaft $350 m$ below the ground level?

Rate of elevator $= 6 m / m i n$
and it was started $10 m$ above the ground level
Depth below ground level $= 350 m$
Total depth $= 350 + 10 = 360$
Time taken $= \frac{360}{6}$ minutes $= 60$ minutes $= 1$ hour