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Projectile Time, Height and Range

An elevator w...

Question

An elevator without a ceiling is ascending with a constant speed of $10 m / s$ . A boy on the elevator shoots a ball directly upward, from a height of $2.0 m$ above te elevator floor. At this time the elevator floor is $28 m$ above the ground. The initial speed of the ball with respect to the elevator is $20 m / s$ . (g= $10 m / s^{2}$ ). What maximum height above the ground does the ball reach?

A

45

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B

30

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C

75

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D

90

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Solution

The correct option is B $75$
absolute initial velocity of the ball is 20+10=30 m/s, thus the max height reached from the point of projection is 45 m. point of projection is itself at a height of 28+2 = 30 m. thus, max height from the ground is 45+30=75m.

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