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Question

# An elevator without a ceiling is ascending with a constant speed of 10m/s. A boy on the elevator shoots a ball directly upward, from a height of 2.0m above te elevator floor. At this time the elevator floor is 28m above the ground. The initial speed of the ball with respect to the elevator is 20m/s. (g= 10m/s2). What maximum height above the ground does the ball reach?

A
45
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B
30
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C
75
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D
90
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Solution

## The correct option is B 75absolute initial velocity of the ball is 20+10=30 m/s, thus the max height reached from the point of projection is 45 m. point of projection is itself at a height of 28+2 = 30 m. thus, max height from the ground is 45+30=75m.

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