wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

An ellipse xz4+yz3=1 confocal with hyperbola x2cos2θy2sin2θ=1 then the set of value of 0

A
R
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
R{nπ,nϵz}
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
R{(2n+1)π2,nϵz}
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
R{nπ2,nϵz}
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C R
Focus of ellipse=ae=a1b2a2
=a2b2
=1
=1
Focus of hyperbola=a1+b2a2
=a2+b2
=sin2θ+cos2θ
=1
=1
The ellipse and hyperbola will be confocal for θϵR.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Ellipse and Terminologies
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon