Question

An enemy aircraft is flying at a height of $875m$ from the surface of the earth with a uniform velocity of $150m/s$ in horizontal direction. When this aircraft is just over an antiaircraft gun a shell is fired from the antiaircraft gun with velocity $v_0$ at an angle ${\theta }_0$ above the horizontal direction. This shell hits the aircraft $35$ second after being fired. Determine $v_0$ and ${\theta }_0$.
$[g=10m/s^2$ and $\tan {53}^{\circ }=4/3]$.

• A. $250m/s,{53}^0$
• B. $25m/s,{53}^0$
• C. $150m/s,{55}^0$
• D. $2oom/s,{45}^0$

Answer 1

The correct option is A $250m/s,{53}^0$

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