CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

An energy of 24.6 eV is required to remove one of the electrons from a neutral helium atom. The energy (in eV) required to remove both the electrons from a neutral helium atom is

A
38.2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
49.2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
51.8
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
79.0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 79.0
After remaining one electron from Helium atom is will become Hydrogen like atom.
Energy required to remove remaining one electron is
E=(13.6)Z2n2=(13.6)2212=56.4 eV
Energy required to remove both electrons is 24.6 eV+54.4 eV=79 eV

flag
Suggest Corrections
thumbs-up
64
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Ionization Enthalpy
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon