An energy of 24.6eV is required to remove one of the electrons from a neutral helium atom. The energy in (eV) required to remove both he electrons from a neutral helium atom is-

38.2

49.2

51.8

79.0

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Solution

$T h e e n e r g y r e q u i r e d t o r e m o b e t h e s e c o n d e l e c t r o n i s E = Z^{2} \times 13.6 e V = 54.4 s o t o t a l e n e r g y r e q u i r e d = 54.4 + 24.6 = 79 e V$

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An energy of 24.6eV is required to remove one of the electrons from a neutral helium atom. The energy in (eV) required to remove both he electrons from a neutral helium atom is- 38.2 49.2 51.8 79.0

The energy required to remobe the second electron isE=Z2×13.6 eV= 54.4so total energy required= 54.4+24.6= 79 eV

An energy of 24.6eV is required to remove one of the electrons from a neutral helium atom. The energy in (eV) required to remove both he electrons from a neutral helium atom is-

38.2

49.2

51.8

79.0

$T h e e n e r g y r e q u i r e d t o r e m o b e t h e s e c o n d e l e c t r o n i s E = Z^{2} \times 13.6 e V = 54.4 s o t o t a l e n e r g y r e q u i r e d = 54.4 + 24.6 = 79 e V$