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Question
An engine operates on the reversible cycles as shown in the figure. The work output from the engine (in kJ/cycle) is (correct to two decimal places).
- 62.5
- 62.5
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Solution
The correct option is A 62.5
Since it is a case of reversible cycle, so work done be equal to the area of P−V cycle. Work out=Area enclosed on P−V diagram
=12(650−400)(2.5−2)
=62.5(kJ/cycle)
Since it is a case of reversible cycle, so work done be equal to the area of P−V cycle. Work out=Area enclosed on P−V diagram
=12(650−400)(2.5−2)
=62.5(kJ/cycle)
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