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Relation Between MA and VR

An engine pum...

Question

An engine pumps up $1000$ $k g$ of coal from a mine $100$ $m$ deep in $0.5 s e c$ . The pump is running with diesel and efficiency of diesel engine is 25 $%$ Then its power consump-
tion will be $(g = 10 m s^{- 1})$ :

20 k W

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80 k W

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10 k W

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50 k W

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Solution

The correct option is A $80 k W$
$O u t p u t P o w e r = \frac{m g h}{t}$

$= \frac{1000 \times 10 \times 100}{0.5} = 2000 k W$

$E f f i c i e n c y = \frac{O u t p u t P o w e r}{I n p u t P o w e r} \times 100$

$25 = \frac{2000}{I n p u t P o w e r}$

$I n p u t P o w e r = \frac{2000}{25} = 80 k W$

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