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Question

An eraser weighing 2 N is pressed against the black board with a force of 5 N. The coefficient of friction is 0.4. How much force parallel to the black board is required to slide the eraser upwards?

A
2N
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B
2.8N
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C
4N
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D
4.8N
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Solution

The correct option is C 4N
Total downward force acting on eraser,
= Frictional force + weight
This is the minimum amount of force required to lift the eraser upwards
=5μ+2=4 N

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