An excess of Cl 2 reacts with ammonia- the products formed are-A- NH 3 and N 2B- NCl 3 and HClC- NCl 3 and N 2D- NH 4 Cl and N 2

The correct option is B N Cl_3 and HClNH_3 +(excess)3Cl_2⟶ NCl_3+3HCl ...

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Reaction with Metals

An excess of ...

Question

An excess of $C l_{2}$ reacts with ammonia, the products formed are:

N H_{3} a n d N_{2}

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N C l_{3} a n d H C l

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N C l_{3} a n d N_{2}

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N H_{4} C l a n d N_{2}

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Solution

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C l_{2}

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N H_{3} + C l_{2} \to N_{2} + N H_{4} C l

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