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An iceberg is...

Question

An iceberg is floating in sea water. The density of ice is $0.92 g m / c m^{3}$ and that of sea water is $1.03 g m / c m^{3}$ . What percentage of the iceberg will be below the surface of water

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Solution

The correct option is C
For the floatation of ice-berg, Weight of ice = upthrust due to displaced water
$V ρ g = V_{i n} σ g \Rightarrow (\frac{ρ}{σ}) V = (\frac{0.92}{1.03}) V = 0.89 V ∴ \frac{V_{i n}}{V} = 0.89 o r 89 %$

Suggest Corrections

Similar questions

1.03 g c m^{- 3}

0.92 g c m^{- 3}

1.03 g / c m^{3}

0.92 g / c m^{3}

917 k g m^{- 3}

1024 k g m^{- 3}

= 917 k g m^{- 3}

= 1.024 \times 10^{3} k g m^{- 3}

^{- 3}

^{- 3}

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