Question

Iceberg floats in sea water with a part of it submerged. The percentage fraction of the ice berg submerged is (Density of ice = 0.9 g cm${}^{-3}$, density of the sea water= 1.1 g cm${}^{-3}$)

• A. 18%
• B. 12%
• C. 10%
• D. 8%.

Answer 1

The correct option is A 18%

$V$ be the volume of the iceberg, x be the volume out of seawater.
The iceberg is floating in sea water then
$V{\rho }_{ice}g=(V-x){\rho }_{seawater}g$
or $V\times 0.9\times g=(V-x)1.1gor0.9V=1.1V-1.1x$
$0.2V=1.1x$
$\therefore \frac{x}{V}=\frac{0.2}{1.1}$
Percentage of fraction of the volume of iceberg above the level of sea water
$\frac{x}{v}\times 100=\frac{0.2}{1.1}\times 100=18\%$