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Question

# An iceberg is floating partially immersed in sea water. The density of sea water is 1.03gcm−3 and that of ice is 0.92 gcm−3. The approximate percentage of total volume of iceberg above the level of sea water is

A
8
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B
11
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C
34
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D
89
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Solution

## The correct option is B 11lets say V is the total volume of the iceberg, and x be the volume of submerged part of iceberg. then according to Archimedes principle, we haveweight of the iceberg= weight of the water displaced (weight of x volume of water)⇒V×0.92×g=x×1.03×g⇒xV=92103 percentage of volume of iceberg submerged in sea water =92103×100=89.32% so percentage of total volume of iceberg above the level of sea water =100−89.32=10.68%≈11%

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